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Solving Equations
9th - 10th , solving systems of equations, 9th - 12th , systems of equations, one step equations, 11.3k plays.
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- 1. Multiple-choice 30 seconds 1 pt What is the first step in solving this equation: 5x + 7 = 12 Divide by 5 Subtract 5 Multiply by 7 Subtract 7
- 2. Multiple-choice 30 seconds 1 pt What is the first step to complete when solving this equation? 10 - 3y = 4 Add 10 Subtract 10 Add 3 Divide by -3
- 3. Multiple-choice 30 seconds 1 pt What is the first step to complete when solving this equation? 3y - 10 = 4 Add 10 Subtract 10 Add 3 Divide by -3
- 4. Multiple-choice 30 seconds 1 pt Solve for x: 8x - 10 = -34 4 3 -3 -24
- 6. Multiple-choice 1 minute 1 pt Solve for the variable. 3x=-27 x=9 x=-30 x=-9 x=-24
- 7. Multiple-choice 2 minutes 1 pt Solve for "x" ? x-9=15 23 6 24 11
- 8. Multiple-choice 3 minutes 1 pt Solve for " x" ? 4x-6=30 9 13 36 4
- 9. Multiple-choice 30 seconds 1 pt h/3=7 10 4 21 2.33
- 10. Multiple-choice 3 minutes 1 pt 2x - 3 + 4x = 27 12 4 5 15
- 11. Multiple-choice 3 minutes 1 pt y - 14 = 66 80 52 79 Answer Not Given
- 12. Multiple-choice 3 minutes 1 pt Solve the equation: 4p = 16 p = 12 p = 64 p = 3 p = 4
- 13. Multiple-choice 30 seconds 1 pt Ted bought a dolphin poster for $12. He now has $5. Write and solve a subtraction equation to find out how much money Ted took to the aquarium. m - 12 = 5 m - 5 = 12 m + 5 = 12 m + 12 = 5
- 14. Multiple-choice 30 seconds 1 pt Cheryl gets paid $8 per hour at her job at the record store. She made a total of $96 last week. Write a multiplication equation to show how many hours she worked last week. 96h = 8 h/96 = 8 8h = 96 h/8 = 96
- 15. Multiple-choice 30 seconds 1 pt Translate: Twelve less than a number 12 - x x - 12 12x x + 12
- 16. Multiple-choice 15 minutes 1 pt Solve: 2x + 1 = 5 3 2 -2 -3
- 17. Multiple-choice 1 minute 1 pt Solve the equation x+8=-22 30 14 -14 -30
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Completing the Square
" Completing the Square " is where we ...
But if you have time, let me show you how to " Complete the Square " yourself.
Say we have a simple expression like x 2 + bx . Having x twice in the same expression can make life hard. What can we do?
Well, with a little inspiration from Geometry we can convert it, like this:
As you can see x 2 + bx can be rearranged nearly into a square ...
... and we can complete the square with (b/2) 2
In Algebra it looks like this:
So, by adding (b/2) 2 we can complete the square.
The result of (x+b/2) 2 has x only once , which is easier to use.
Keeping the Balance
Now ... we can't just add (b/2) 2 without also subtracting it too! Otherwise the whole value changes.
So let's see how to do it properly with an example:
The result:
x 2 + 6x + 7 = (x+3) 2 − 2
And now x only appears once, and our job is done!
A Shortcut Approach
Here is a quick way to get an answer. You may like this method.
First think about the result we want: (x+d) 2 + e
After expanding (x+d) 2 we get: x 2 + 2dx + d 2 + e
Now see if we can turn our example into that form to discover d and e
Example: try to fit x 2 + 6x + 7 into x 2 + 2dx + d 2 + e
Now we can "force" an answer:
- We know that 6x must end up as 2dx , so d must be 3
- Next we see that 7 must become d 2 + e = 9 + e , so e must be −2
And we get the same result (x+3) 2 − 2 as above!
Now, let us look at a useful application: solving Quadratic Equations ...
Solving General Quadratic Equations by Completing the Square
We can complete the square to solve a Quadratic Equation (find where it is equal to zero).
But a general Quadratic Equation can have a coefficient of a in front of x 2 :
ax 2 + bx + c = 0
But that is easy to deal with ... just divide the whole equation by "a" first, then carry on:
x 2 + (b/a)x + c/a = 0
Now we can solve a Quadratic Equation in 5 steps:
- Step 1 Divide all terms by a (the coefficient of x 2 ).
- Step 2 Move the number term ( c/a ) to the right side of the equation.
- Step 3 Complete the square on the left side of the equation and balance this by adding the same value to the right side of the equation.
We now have something that looks like (x + p) 2 = q, which can be solved rather easily:
- Step 4 Take the square root on both sides of the equation.
- Step 5 Subtract the number that remains on the left side of the equation to find x .
OK, some examples will help!
Example 1: Solve x 2 + 4x + 1 = 0
Step 1 can be skipped in this example since the coefficient of x 2 is 1
Step 2 Move the number term to the right side of the equation:
Step 3 Complete the square on the left side of the equation and balance this by adding the same number to the right side of the equation.
(b/2) 2 = (4/2) 2 = 2 2 = 4
Step 4 Take the square root on both sides of the equation:
Step 5 Subtract 2 from both sides:
Example 2: Solve 5x 2 – 4x – 2 = 0
Step 1 Divide all terms by 5
Step 3 Complete the square on the left side of the equation and balance this by adding the same number to the right side of the equation:
(b/2) 2 = (0.8/2) 2 = 0.4 2 = 0.16
Step 5 Subtract (-0.4) from both sides (in other words, add 0.4):
Why "Complete the Square"?
Why complete the square when we can just use the Quadratic Formula to solve a Quadratic Equation?
Well, one reason is given above, where the new form not only shows us the vertex, but makes it easier to solve.
There are also times when the form ax 2 + bx + c may be part of a larger question and rearranging it as a(x+ d ) 2 + e makes the solution easier, because x only appears once.
For example "x" may itself be a function (like cos(z) ) and rearranging it may open up a path to a better solution.
Also Completing the Square is the first step in the Derivation of the Quadratic Formula
Just think of it as another tool in your mathematics toolbox.
Footnote: Values of "d" and "e"
How did I get the values of d and e from the top of the page?
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Course: Algebra 1 > Unit 6
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Systems of equations with substitution: -3x-4y=-2 & y=2x-5
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Quiz 1: 5 questions Practice what you've learned, and level up on the above skills Analyzing the number of solutions to linear equations Linear equations with unknown coefficients Quiz 2: 5 questions Practice what you've learned, and level up on the above skills Multi-step inequalities Compound inequalities
Solving exponential equations using properties of exponents Introduction to rate of exponential growth and decay Interpreting the rate of change of exponential models (Algebra 2 level) Constructing exponential models according to rate of change (Algebra 2 level) Advanced interpretation of exponential models (Algebra 2 level) Distinguishing betwe...
Study Guides Basic Math & Pre-Algebra Quiz: Solving Simple Equations Preliminaries Multiplying and Dividing Using Zero Common Math Symbols Quiz: Ways to Show Multiplication and Division, Multiplying and Dividing by Zero, and Common Math Symbols Properties of Basic Mathematical Operations Quiz: Properties of Basic Mathematical Operations
2023 Edition Algebra Practice Test Test your knowledge of introductory Algebra with this Algebra practice exam. Whether you are studying for a school math test or looking to test your math skills, this free practice test will challenge your knowledge of algebra. View Answers as You Go View 1 Question at a Time Bookmark Page
Unit 1: Algebra foundations 0/700 Mastery points Overview and history of algebra Introduction to variables Substitution and evaluating expressions Combining like terms Introduction to equivalent expressions Division by zero Unit 2: Solving equations & inequalities 0/1100 Mastery points
Course Try it risk-free for 30 days Instructions: Choose an answer and hit 'next'. You will receive your score and answers at the end. question 1 of 3 In the equation 5x - 7 = 8, which number is...
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Algebra Quiz: Test your algebra skills by answering questions. This quiz asks you to solve algebraic linear and quadratic equations of one variable. Choose difficulty level, question types, and time limit. Algebra Quiz is one of the Interactivate assessment quizzes. On a mission to transform learning through computational thinking, Shodor is ...
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Preview this quiz on Quizizz. quiz for 8th grade students. Find other quizzes for and more on Quizizz for free! ... Algebraic equations Mathematics. 64% accuracy. 1.4K . plays ... Write and solve a subtraction equation to find out how much money Ted took to the aquarium. m - 12 = 5. m - 5 = 12. m + 5 = 12. m + 12 = 5. 14. Multiple-choice. 30 ...
Step 1 Divide all terms by a (the coefficient of x 2).; Step 2 Move the number term (c/a) to the right side of the equation.; Step 3 Complete the square on the left side of the equation and balance this by adding the same value to the right side of the equation.; We now have something that looks like (x + p) 2 = q, which can be solved rather easily: Step 4 Take the square root on both sides of ...
Learn for free about math, art, computer programming, economics, physics, chemistry, biology, medicine, finance, history, and more. ... Same thing to both sides of equations. Intro to two-step equations. Two-step equations intuition. Worked example: two-step equations. Two-step equations. Math > 7th grade >
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Math Algebra basics 11,200 Unit 1: Foundations 0/3200 Mastery points Negative numbers Absolute value Exponents Square roots Order of operations Fractions Decimals, fractions and percentages Operations with decimals Area of triangles Circumference and area of circles Unit 2: Algebraic expressions 0/1100 Mastery points
Basics of Algebra; Equation Basics Worksheet; Equation Basics Worksheet. Solve each equation. ... Quiz: Equation: -3 + 2x = 11 . Show answer|Show step-by-step | ... Brush up on your knowledge of the techniques needed to solve problems on this page. Equation Calculator Will automatically solve equations and show all of the required work.
In algebra, a quadratic equation (from Latin quadratus 'square') is any equation that can be rearranged in standard form as where x represents an unknown value, and a, b, and c represent known numbers, where a ≠ 0. (If a = 0 and b ≠ 0 then the equation is linear, not quadratic.) The numbers a, b, and c are the coefficients of the equation ...
This type of equation creates a line where each point on the line represents an (x, y) ordered pair that is a solution to the equation. When you have 2 equations with the same 2 variables, then you have a system of linear equations. The solution to the system is the point (or points) that the 2 linear equations have in common. Hope this helps.