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Course: Algebra 1 Β  > Β  Unit 2

  • Why we do the same thing to both sides: Variable on both sides
  • Intro to equations with variables on both sides
  • Equations with variables on both sides: 20-7x=6x-6

Equations with variables on both sides

  • Equation with variables on both sides: fractions
  • Equations with variables on both sides: decimals & fractions
  • Equation with the variable in the denominator
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  • a simplified improper fraction, like 7 / 4 ‍  
  • a mixed number, like 1   3 / 4 ‍  
  • an exact decimal, like 0.75 ‍  
  • a multiple of pi, like 12   pi ‍   or 2 / 3   pi ‍  

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2.3: Solve Equations with Variables and Constants on Both Sides

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Learning Objectives

By the end of this section, you will be able to:

  • Solve an equation with constants on both sides
  • Solve an equation with variables on both sides
  • Solve an equation with variables and constants on both sides

Before you get started, take this readiness quiz.

  • Simplify: 4y−9+9. If you missed this problem, review Exercise 1.10.20 .

Solve Equations with Constants on Both Sides

In all the equations we have solved so far, all the variable terms were on only one side of the equation with the constants on the other side. This does not happen all the time—so now we will learn to solve equations in which the variable terms, or constant terms, or both are on both sides of the equation.

Our strategy will involve choosing one side of the equation to be the “variable side”, and the other side of the equation to be the “constant side.” Then, we will use the Subtraction and Addition Properties of Equality to get all the variable terms together on one side of the equation and the constant terms together on the other side.

By doing this, we will transform the equation that began with variables and constants on both sides into the form \(ax=b\). We already know how to solve equations of this form by using the Division or Multiplication Properties of Equality.

Example \(\PageIndex{1}\)

Solve: \(7x+8=−13\).

In this equation, the variable is found only on the left side. It makes sense to call the left side the “variable” side. Therefore, the right side will be the “constant” side. We will write the labels above the equation to help us remember what goes where.

This figure shows the equation 7x plus 8 equals negative 13, with the left side of the equation labeled “variable”, written in red, and the right side of the equation labeled “constant”, written in red.

Since the left side is the “xx”, or variable side, the 8 is out of place. We must “undo” adding 8 by subtracting 8, and to keep the equality we must subtract 8 from both sides.

Try It \(\PageIndex{2}\)

Solve: \(3x+4=−8\).

\(x=−4\)

Try It \(\PageIndex{3}\)

Solve: \(5a+3=−37\).

\(a=−8\)

Example \(\PageIndex{4}\)

Solve: \(8y−9=31\).

Notice, the variable is only on the left side of the equation, so we will call this side the “variable” side, and the right side will be the “constant” side. Since the left side is the “variable” side, the 9 is out of place. It is subtracted from the 8y, so to “undo” subtraction, add 9 to both sides. Remember, whatever you do to the left, you must do to the right.

Try It \(\PageIndex{5}\)

Solve: \(5y−9=16\).

Try It \(\PageIndex{6}\)

Solve: \(3m−8=19\).

Solve Equations with Variables and Constants on Both Sides

The next example will be the first to have variables and constants on both sides of the equation. It may take several steps to solve this equation, so we need a clear and organized strategy.

Example \(\PageIndex{7}\)

Solve: \(9x=8x−6\).

Here the variable is on both sides, but the constants only appear on the right side, so let’s make the right side the “constant” side. Then the left side will be the “variable” side.

Try It \(\PageIndex{8}\)

Solve: \(6n=5n−10\).

\(n = -10\)

Try It \(\PageIndex{9}\)

Solve: \(-6c = -7c - 1\)

Example \(\PageIndex{10}\)

Solve: \(5y - 9 = 8y\)

The only constant is on the left and the y’s are on both sides. Let’s leave the constant on the left and get the variables to the right.

Try It \(\PageIndex{11}\)

Solve: \(3p−14=5p\).

Try It \(\PageIndex{12}\)

Solve: \(8m + 9 = 5m\)

Example \(\PageIndex{13}\)

Solve: \(12x = -x + 26\)

The only constant is on the right, so let the left side be the “variable” side.

Try It \(\PageIndex{14}\)

Solve: \(12j = -4j + 32\)

Try It \(\PageIndex{15}\)

Solve: \(8h = -4h + 12\)

Example \(\PageIndex{16}\): How to Solve Equations with Variables and Constants on Both Sides

Solve: \(7x + 5 = 6x + 2\)

This figure is a table that has three columns and four rows. The first column is a header column, and it contains the names and numbers of each step. The second column contains further written instructions. The third column contains math. On the top row of the table, the first cell on the left reads: “Step 1. Choose which side will the “variable” side—the other side will be the “constant” side.” The text in the second cell reads: “The variable terms are 7 x and 6 x. Since 7 is greater than 6, we will make the left side the “x” side and so the right side will be the “constant” side.” The third cell contains the equation 7 x plus 5 equals 6 x plus 2, and the left side of the equation is labeled “variable” written in red, and the right side of the equation is labeled “constant” written in red.

Try It \(\PageIndex{17}\)

Solve: \(12x+8=6x+2\).

\(x=−1\)

Try It \(\PageIndex{18}\)

Solve: \(9y+4=7y+12\).

​​​​​​ We’ll list the steps below so you can easily refer to them. But we’ll call this the ‘Beginning Strategy’ because we’ll be adding some steps later in this chapter.

BEGINNING STRATEGY FOR SOLVING EQUATIONS WITH VARIABLES AND CONSTANTS ON BOTH SIDES OF THE EQUATION.

  • Choose which side will be the “variable” side—the other side will be the “constant” side.
  • Collect the variable terms to the “variable” side of the equation, using the Addition or Subtraction Property of Equality.
  • Collect all the constants to the other side of the equation, using the Addition or Subtraction Property of Equality.
  • Make the coefficient of the variable equal 1, using the Multiplication or Division Property of Equality.
  • Check the solution by substituting it into the original equation.

In Step 1, a helpful approach is to make the “variable” side the side that has the variable with the larger coefficient. This usually makes the arithmetic easier.

Example \(\PageIndex{19}\)

Solve: \(8n−4=−2n+6\).

In the first step, choose the variable side by comparing the coefficients of the variables on each side.

Try It \(\PageIndex{20}\)

Solve: \(8q - 5 = -4q + 7\)

Try It \(\PageIndex{21}\)

Solve: \(7n - 3 = n + 3\)

Example \(\PageIndex{22}\)

Solve: \(7a -3 = 13a + 7\)

Since 13>7, make the right side the “variable” side and the left side the “constant” side.

Try It \(\PageIndex{23}\)

Solve: \(2a - 2 = 6a + 18\)

Try It \(\PageIndex{24}\)

Solve: \(4k -1 = 7k + 17\)

In the last example, we could have made the left side the “variable” side, but it would have led to a negative coefficient on the variable term. (Try it!) While we could work with the negative, there is less chance of errors when working with positives. The strategy outlined above helps avoid the negatives!

To solve an equation with fractions, we just follow the steps of our strategy to get the solution!

Example \(\PageIndex{25}\)

Solve: \(\frac{4}{5}x + 6 = \frac{1}{4}x - 2\)

Since \(\frac{5}{4} > \frac{1}{4}\), make the left side the “variable” side and the right side the “constant” side.

Try It \(\PageIndex{26}\)

Solve: \(\frac{7}{8}x - 12 = -\frac{1}{8}x - 2\)

Try It \(\PageIndex{27}\)

Solve: \(\frac{7}{6}x + 11 = \frac{1}{6}y + 8\)

We will use the same strategy to find the solution for an equation with decimals.

Example \(\PageIndex{28}\)

Solve: \(7.8x+4=5.4x−8\).

Since \(7.8>5.4\), make the left side the “variable” side and the right side the “constant” side.

Try It \(\PageIndex{29}\)

Solve: \(2.8x + 12 = -1.4x - 9\)

Try It \(\PageIndex{30}\)

Solve: \(3.6y + 8 = 1.2y - 4\)

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How to Solve Equations with Variables on Both Sides

Last Updated: March 11, 2023 Fact Checked

This article was co-authored by JohnK Wright V . JohnK Wright V is a Certified Math Teacher at Bridge Builder Academy in Plano, Texas. With over 20 years of teaching experience, he is a Texas SBEC Certified 8-12 Mathematics Teacher. He has taught in six different schools and has taught pre-algebra, algebra 1, geometry, algebra 2, pre-calculus, statistics, math reasoning, and math models with applications. He was a Mathematics Major at Southeastern Louisiana and he has a Bachelor of Science from The University of the State of New York (now Excelsior University) and a Master of Science in Computer Information Systems from Boston University. This article has been fact-checked, ensuring the accuracy of any cited facts and confirming the authority of its sources. This article has been viewed 186,107 times.

To study algebra, you will see equations that have a variable on one side, but later on you will often see equations that have variables on both sides. The most important thing to remember when solving such equations is that whatever you do to one side of the equation, you must do to the other side. Using this rule, it is easy to move variables around so that you can isolate them and use basic operations to find their value.

Solving Equations with One Variable on Both Sides

Step 1 Apply the distributive property, if necessary.

Solving System Equations with Two Variables

Step 1 Isolate a variable in one equation.

Solving Example Problems

Step 1 Try this problem using the distributive property with one variable:

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  • ↑ https://www.khanacademy.org/math/cc-sixth-grade-math/cc-6th-expressions-and-variables/cc-6th-distributive-property/v/the-distributive-property
  • ↑ https://www.virtualnerd.com/algebra-1/linear-equations-solve/variables-both-sides-equations/variables-both-sides-solution/variables-grouping-symbols-both-sides
  • ↑ https://www.youtube.com/watch?v=hrAOSknrYiI&t=296s
  • ↑ https://www.khanacademy.org/math/cc-sixth-grade-math/cc-6th-expressions-and-variables/cc-6th-evaluating-expressions/v/expression-terms-factors-and-coefficients
  • ↑ https://www.virtualnerd.com/pre-algebra/linear-functions-graphing/system-of-equations/solving-systems-equations/two-equations-two-variables-substitution

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Solving Equations with Variables on Both Sides

Solving Equations with Variables on Both Sides Video

Hello! Today we’re going to take a look at solving equations with variables on both sides . The solving process for these types of problems will look similar to more simple forms of solving equations , it will just require a few additional steps. So, let’s start by taking a look at an example.

\(5x+9=3x-7\)

To solve problems like these, you will want to get all the variable terms on one side of the equation and all the constant terms on the other side of the equation. It doesn’t matter which side either one goes on, just make sure that all the variable terms are on one side and all the constants are on the other side. So, for this, I’m going to get the \(x\)-terms on the left side of the equation. So, to do that, we’ll subtract \(3x\) from both sides.

\(5x-3x+9=3x-3x-7\)

If you wanted to subtract \(5x\) from both sides and get the \(x\)-terms on the right side of the equation, that would be totally fine as well.

\(2x+9=-7\)

So now, to get the constants on the other side, we’re going to want to subtract 9 from both sides.

\(2x+9-9=-7-9\)   \(2x=-16\)

And finally, to solve the equation, we need to get \(x\) by itself, so we do that by dividing both sides by 2.

\(\frac{2x}{2}=\frac{-16}{2}\)   \(x=-8\)

Let’s take a look at another problem.

\(-2x+13=6x-31\)

This time, we are going to solve for the variable on the right side. So, to do this, we’re going to start by adding \(2x\) to both sides of the equation β€” that will get our \(x\)-terms on the right side.

\(-2x+2x+13=6x+2x-31\)   \(13=8x-31\)

Now, we want to get our constants on the left side so we’ll add 31 to both sides.

\(13+31=8x-31+31\)   \(44=8x\)

And finally, to get \(x\) by itself, we divide both sides by 8.

\(\frac{44}{8}=\frac{8x}{8}\)   \(\frac{44}{8}=x\)

Now, this fraction isn’t in most simplest form, so the best thing to do is to simplify it. The way that we can simplify this fraction is by dividing both the numerator and denominator by 4.

\(x=\frac{44}{8}=\frac{44\div 4}{8\div 4}=\frac{11}{2}\)   \(x=\frac{11}{2}\)

Let’s take a look at one more problem before we go.

\(4x+17=-9x-9\)

So, first we’re going to add \(9x\) to both sides. If you wanted to subtract 4x from both sides and solve for \(x\) on the right side of the equation, that would totally be acceptable as well. The reason I chose to add \(9x\) to both sides is because I don’t particularly like working with negative numbers when I don’t have to. So I’m adding \(9x\) so that I’ll have a positive number of \(x\)‘s on the left side. So, that’s why I chose that, but if you like negatives and want to do that, you are more than welcome to.

\(4x+9x+17=-9x+9x-9\)   \(13x+17=-9\)

Now I’m going to subtract 17 from both sides of our equation.

\(13x+17-17=-9-17\)   \(13x=-26\)

So, notice we have a negative over here, so we’re dealing with negatives anyways, so it’s just up to you back at this first step if you want to have negative \(x\)-values or negative constants. Either way will get you the right answer. So to get \(x\) by itself and solve for \(x\) we’re going to divide by 13 on both sides.

\(\frac{13x}{13}=\frac{-26}{13}\)   \(x=-2\)

I hope that this video gave you more confidence in solving equations. Thanks for watching and happy studying!

Solving Equations with Variables on Both Sides Practice Questions

  Solve the equation: \(4x+9=25+2x\).

To get the variable terms on the left side, subtract \(2x\) from both sides of the equation.

\(4x+9-2x=25+2x-2x\) \(2x+9=25\)

Now, subtract 9 from both sides.

\(2x+9-9=25-9\) \(2x=16\)

Finally, divide both sides by 2.

\(\frac{2x}{2}=\frac{16}{2}\)

  Solve the equation: \(-5x-16=-7x+4\).

To get the variable terms on the left side, add \(7x\) to both sides of the equation.

\(-5x-16+7x=-7x+4+7x\) \(2x-16=4\)

Now, add 16 to both sides.

\(2x-16+16=4+16\) \(2x=20\)

Then, divide both sides by 2.

\(\frac{2x}{2}=\frac{20}{2}\)

  Solve the equation: \(6x-11=2x+27\).

\(6x-11-2x=2x+27-2x\) \(4x-11=27\)

Now, add 11 to both sides.

\(4x-11+11=27+11\) \(4x=38\)

Then, divide both sides by 4.

\(\frac{4x}{4}=\frac{38}{4}\)

\(x=\frac{38}{4}\)

Reduce the fraction by 2, to write the answer in simplest form.

\(x=\frac{38\div2}{4\div2}=\frac{19}{2}\)

  You charge homeowners in your neighborhood a flat fee of $20 plus $10 per hour to rake leaves from their yards. Your friend charges a flat fee of $35 plus $7 per hour for the same service. How many hours will each of you need to work to make the same amount of money raking leaves in your neighborhood?

Let \(x\) be the number of hours you both work. You have a flat fee of $20 and are charging $10 per hour, the amount of money you make for working \(x\) number of hours is \(20+10x\). Your friend has a flat fee of $35 and charges $7 per hour, so the amount of money your friend makes for working \(x\) number of hours is \(35+7x\). To determine how many hours you each need to work to make the same amount of money, we need to set the two expressions equal to each other.

\(20+10x=35+7x\)

To get the variable terms on the left side, subtract \(7x\) from both sides of the equation.

\(20+10x-7x=35+7x-7x\) \(20+3x=35\)

Now, subtract 20 from both sides.

\(20+3x-20=35-20\) \(3x=15\)

Finally, divide both sides by 3.

\(\frac{3x}{3}=\frac{15}{3}\)

  You and your friend are on the school track team. You each spend a week running alone, then you and your friend run at the same time. During the week alone, you ran 16 miles and your friend ran 23 miles. While running at the same time, you run 4 miles each day and your friend runs 3 miles each day. How many days after you starting running together will you and your friend have run the same number of miles?

Let \(x\) be the number days you each run after the week of running alone. Since you run 4 miles each day, you run \(4x\) miles in \(x\) days. Similarly, since your friend runs 3 miles each day, she runs \(3x\) miles in \(x\) days. During the week you each ran alone, you ran 16 miles, and your friend ran 23 miles. So, after the first week of running alone, you will have run \(16+4x\) miles, and your friend will have run \(23+3x\) miles.

Now, set the expressions equal to each other to find how many days it will take for you and your friend to run the same number of miles.

\(16+4x=23+3x\)

To get the variable terms on the left side, subtract \(3x\) from both sides of the equation.

\(16+4x-3x=23+3x-3x\) \(16+x=23\)

Now, subtract 16 from both sides.

\(16+x-16=23-16\) \(x=7\)

Therefore, 7 days after you and your friend started running together, you both will have run the same number of miles.

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Solving Equations With Variables On Both Sides

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Multi-Step Equations Variables on Both Sides Digital Math Escape Room Activity

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An engaging algebra escape room activity for solving multi-step equations with variables on both sides. Students must unlock 5 locks by solving 20 equations, most with x on both sides. Some equations involve distribution and some include fractions. Questions are grouped 4 per puzzle, resulting in five 4-letter codes that will unlock all 5 locks.

The entire activity is housed in one GOOGLE Form. There are no links to outside websites. The 4-letter codes are set with answer validation so that students cannot move to the next puzzle until they enter the correct code. Includes answer key.

To add the digital escape room to your Google Drive : please open the PDF and click the button on page 3.

A printable PDF version has also been added to the file. Students can work in groups, each group starting at a different puzzle. Once done, students check the NEXT STEP box for which puzzle to visit next.

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  1. solving equations with variables on both sides Worksheet

    solve equations with variables on both sides quiz

  2. Equations With Variables On Both Sides Worksheet, Practice, And Examples

    solve equations with variables on both sides quiz

  3. Solving Equations With Variables On Both Sides Worksheet

    solve equations with variables on both sides quiz

  4. 1.5

    solve equations with variables on both sides quiz

  5. Solving Linear Equations With Variables On Both Sides Worksh

    solve equations with variables on both sides quiz

  6. Solving linear equations with the variable on both sides

    solve equations with variables on both sides quiz

VIDEO

  1. ex 2 Solving equations variables on both sides

  2. August 13, 2023

  3. Solving Equations with Variables on both sides Day 2

  4. 3-4 Solve Equations with Variables on Both Sides

  5. 1.3A Solving Equations with Variables on Both Sides

  6. Solving Equations w/Variables on Both Sides 4

COMMENTS

  1. Equations with variables on both sides (practice)

    Algebra 1 > Solving equations & inequalities > Linear equations with variables on both sides Equations with variables on both sides Google Classroom Solve for f . βˆ’ f + 2 + 4 f = 8 βˆ’ 3 f f = Stuck? Review related articles/videos or use a hint. Report a problem Start over Do 4 problems

  2. Solving Equations With Variables on Both Sides Quiz

    Equations can have variables on both sides. Standard techniques for solving apply, but one more step must be added in order to solve the equation correctly. The variable must be isolated on one side of the equation. Example: 4x - 1 = 2x + 7 4x - 2x - 1 = 2x - 2x + 7 Subtract 2x from both sides 2x - 1 = 7 2x - 1 + 1 = 7 + 1 Add 1 to both sides ...

  3. Solving Equations with Variables on Both Sides

    Solving Equations with Variables on Both Sides | 2.4K plays | Quizizz Solving Equations with Variables on Both Sides Sharnae Terry 2.4K 9 questions 1. Multiple Choice 1.5 minutes 1 pt Solve for x: 5x - 14 = 8x + 4 x = 6 x = -6 x = -18/13 x = 10/3 2. Multiple Choice 1.5 minutes 1 pt Solve for f: f - 4 = 6f + 26 f = -5 f = 5 f = 6 f = -6 3.

  4. Solving Linear Equations: Variables on Both Sides: Quiz

    A. x=-5. Solve the equation. y + 6 = -3y + 26. C. y=5. What is the solution to the linear equation? d - 10 - 2d + 7 = 8 + d - 10 - 3d. C. d=1. The levels of mercury in two different bodies of water are rising. In one body of water the initial measure of mercury is 0.05 parts per billion (ppb) and is rising at a rate of 0.1 ppb each year.

  5. Solving Linear Equations: Variables on Both Sides Flashcards

    Learn how to solve linear equations with variables on both sides using Quizlet flashcards. Practice with examples like 8 - 2x = -8x + 14 and -3/4m -1/2 = 2 + 1/4m and test your skills with interactive quizzes.

  6. Solve linear equations with variables on both sides

    Test prep Awards Improve your math knowledge with free questions in "Solve linear equations with variables on both sides" and thousands of other math skills.

  7. solving equations with variables on both sides Flashcards

    solving equations with variables on both sides Flashcards | Quizlet solving equations with variables on both sides 3.5 (12 reviews) 7x - 17 = 4x + 1 Click the card to flip πŸ‘† x = 6 Click the card to flip πŸ‘† 1 / 12 Flashcards Learn Test Match Q-Chat Created by abeazley Students also viewed Cell Theory, Cells - Cell Theory Teacher 15 terms MRS_LV

  8. 8.4: Solve Equations with Variables and Constants on Both Sides)

    Solve an Equation with Constants on Both Sides. You may have noticed that in all the equations we have solved so far, all the variable terms were on only one side of the equation with the constants on the other side. This does not happen all the timeβ€”so now we'll see how to solve equations where the variable terms and/or constant terms are on both sides of the equation.

  9. 2.3: Solve Equations with Variables and Constants on Both Sides

    Example 2.3.19. Solve: 8n βˆ’ 4 = βˆ’ 2n + 6. Solution. In the first step, choose the variable side by comparing the coefficients of the variables on each side. Since 8 > βˆ’ 2, make the left side the "variable" side. We don't want variable terms on the right sideβ€”add 2n to both sides to leave only constants on the right.

  10. How to Solve Equations with Variables on Both Sides

    You should now have the variable on one side of the equation. For example: 20 βˆ’ 4 x + 4 x = 8 x + 8 + 4 x {\displaystyle 20-4x+4x=8x+8+4x} 20 = 12 x + 8 {\displaystyle 20=12x+8} 5. Move the constants to one side of the equation, if necessary. You want the variable term on one side, and the constant on the other side.

  11. Solving Equations with Variables on Both Sides

    And finally, to solve the equation, we need to get x x by itself, so we do that by dividing both sides by 2. 2x2 = βˆ’16 2 2 x 2 = βˆ’ 16 2. x = βˆ’8 x = βˆ’ 8. Let's take a look at another problem. βˆ’2x + 13 = 6x βˆ’ 31 βˆ’ 2 x + 13 = 6 x βˆ’ 31. This time, we are going to solve for the variable on the right side. So, to do this, we're ...

  12. Solving Equations With Variables On Both Sides

    One solution. Explanation. The given equation is a linear equation. To solve it, we can combine like terms and isolate the variable. By adding 5q to both sides, we get -9 = 9q. Dividing both sides by 9, we find that q = -1. Therefore, there is one solution for the equation, which is q = -1. Rate this question: 7.

  13. Solving Equations With Variables on Both Sides

    Mathematics 8th grade Solving Equations With Variables on Both Sides Jeremy Sanders 4.7K plays 15 questions Copy & Edit Live Session Assign Show Answers See Preview 1. Multiple Choice 5 minutes 1 pt Solve for f: f - 4 = 6f + 26 f = -5 f = 5 f = 6 f = -6 2. Multiple Choice 5 minutes 1 pt Solve for x: 5x - 14 = 8x + 4 x = 6 x = -6 x = -18/13 x = 10/3

  14. Extra Practice: Equations w/ variable on both sides

    Answers to Extra Practice: Equations w/ variable on both sides 1) {βˆ’7} 5) {0} 9) {βˆ’1} 13) {7} 17) {βˆ’4} 21) {βˆ’7} 25) {βˆ’6} 29) {1} 33) {0} 37) {4} 41) {βˆ’3} 45) {1} Β©2 B2j0L1C3g yKUuRtLaG oSOo2fItBwRaHrDeJ 3LrLcCQ.0 9 NA4lylf frbiDgehotosF er8e4sEeqrVv1e8db.z 6 NMNakduej xwKi9tnha JIMnAfNiNnaigtWej QAcllgZeUbarNaF X1f.8 -7- Algebra 1 0507

  15. solving equations with variables on both sides

    solving equations with variables on both sides Flashcards | Quizlet solving equations with variables on both sides STUDY Flashcards Learn Write Spell Test PLAY Match Gravity x=6 Click card to see definition πŸ‘† 7x - 17 = 4x + 1 Click again to see term πŸ‘† 1/12 Previous ← Next β†’ Flip Space Created by venetia_ricchio TEACHER Terms in this set (12) x=6

  16. Solve equations with variables on both sides

    Improve your math knowledge with free questions in "Solve equations with variables on both sides" and thousands of other math skills.

  17. Solving Equations with Variables on Both Sides

    Solving Equations with Variables on Both Sides Ashley Joughin 1.6K 24 questions 1. Multiple Choice 1 minute 1 pt Solve for f: f - 4 = 6f + 26 f = -5 f = 5 f = 6 f = -6 2. Multiple Choice 2 minutes 1 pt Solve for x: 5x - 14 = 8x + 4 x = 6 x = -6 x = -18/13 x = 10/3 3. Multiple Choice 5 minutes 1 pt Solve for x: 4 (1-x)+3x=-2 (x+1) x = -6 x = 6 x = 3

  18. Equation Calculator

    The golden rule for solving equations is to keep both sides of the equation balanced so that they are always equal. How do you simplify equations? To simplify equations, combine like terms, remove parethesis, use the order of operations. Show more Why users love our Equation Calculator

  19. Solving equations with variables on both sides Flashcards

    Arithmetic Multiplication Solving equations with variables on both sides Flashcards Learn Test Match Q-Chat Flashcards Learn Test Match Q-Chat Get a hint 7 Click the card to flip πŸ‘† 8x = 3x + 35 Click the card to flip πŸ‘† 1 / 19 1 / 19 Flashcards Learn Test Match Q-Chat Tammy_Green5Teacher Top creator on Quizlet Share Students also viewed TENER

  20. Multi-Step Equations Variables on Both Sides Digital Math Escape ...

    An engaging algebra escape room activity for solving multi-step equations with variables on both sides. Students must unlock 5 locks by solving 20 equations, most with x on both sides. Some equations involve distribution and some include fractions. Questions are grouped 4 per puzzle, resulting in five 4-letter codes that will unlock all 5 locks.

  21. Equations with Variables on Both Sides Flashcards

    What is the first step in solving the equation: 3x + 2 = 10. Subtract 2 from each side. What is the first step in solving the equation: 4x - 20 = 80. Add 20 to both sides. What is the first step in solving the equation: 2x = 24. Divide both sides by 2. What is the first step in solving the equation: 0.5x = 48. Divide both sides by 0.5.

  22. Solving Equations with Variables on Both Sides Flashcards

    Solving Equations with Variables on Both Sides. Flashcards; Learn; Test; Match; Q-Chat; Get a hint. 5x+7=9+7x. Click the card to flip πŸ‘† ... Solving Equations and Inequalities, Solving Equations and Inequalities. Teacher 33 terms. MrsTurrubiarte. Preview. Test directory south line. 67 terms. demidamico99.